Hi to you all,
I'm just struggling with a regex problem and I'm pretty sure that I'm missing sth obvious... :confused:
I need a regex to feed my grep in order to find lines that contain one string but not the other.
Here's the data example:
I want all lines with "UserID1" not containing "foobuzz". I tried this one:
But it gives me both lines. (I have the "LC_ALL=C" workaround from a RedHat article, otherwise I get a core dump for free. ;-) )
What's wrong with me, uhm, with the regex?
And yes, it should be grep because the new regex will be part of an existing regex file which is used by a script in order to grep some gigabytes of data multiple times a day. I don't know if it would be faster with awk or sth like this. Any advice is appreciated!
I will get back to you tomorrow - it's late, I'm the last one in the office, sun is gone... ;-)
Best regards
Stephan
Additional informations:
I'm just struggling with a regex problem and I'm pretty sure that I'm missing sth obvious... :confused:
I need a regex to feed my grep in order to find lines that contain one string but not the other.
Here's the data example:
Code:
2015-04-08 19:04:55,926|xxxxxxxxxx| |foobar| |INFO |REQUEST|UserID1:42 | yeah
2015-04-08 19:04:56,157|yyyyyyyyyy| |foobuzz| |INFO |REQUEST|UserID1:23 | ohnoooCode:
LC_ALL=C grep -P '(?!foobuzz).*UserID1.*' example.txtWhat's wrong with me, uhm, with the regex?
And yes, it should be grep because the new regex will be part of an existing regex file which is used by a script in order to grep some gigabytes of data multiple times a day. I don't know if it would be faster with awk or sth like this. Any advice is appreciated!
I will get back to you tomorrow - it's late, I'm the last one in the office, sun is gone... ;-)
Best regards
Stephan
Additional informations:
Code:
LSB Version: :base-4.0-amd64:base-4.0-noarch:core-4.0-amd64:core-4.0-noarch
Distributor ID: RedHatEnterpriseServer
Description: Red Hat Enterprise Linux Server release 6.6 (Santiago)
Release: 6.6
Codename: SantiagoCode:
GNU grep 2.6.3
